Show Pop Up Only Once Throughout One Navigation Of The Site
Solution 1:
you could use document.referrer, and check if the previous page is one of your domain. But not all visitors/browsers will return this value for security reasons.
So this is unreliable.
Solution 2:
Use a plugin like jQuery Cookie, then simply do:
if(!$.cookie("popup"))
{
your_popup_function();
$.cookie("popup",true);
}
Edit: since you edited your question regarding your definition of "first time visit", I'd advise the approach Walter Brand suggested, using the referrer. Taken from this post:
document.referrer.indexOf(location.protocol + "//" + location.host) === 0;
Solution 3:
Hi i did this solution while solving the client requirement "to show pop-up only once throughout navigating to different pages of the site" and it works good for me. I did it using cookie and setting the cookie value to the cookie creation time than i make the difference of the cookie value with current time using javascript setInterval function and compare the difference with the time on which i want to show the pop-up and it's work.
$(document).ready(function()
{
var myVar="";
functiongetCookie(name)
{
var re = newRegExp(name + "=([^;]+)");
var value = re.exec(document.cookie);
return (value != null) ? unescape(value[1]) : null;
}
functioncallagain()
{
if(!getCookie("magazine"))
{
var c1= newDate();
var c2=c1.getTime();
document.cookie="magazine="+c2;
}
var cvalue= getCookie("magazine");
var cvalue2=parseInt(cvalue);
myVar=setInterval(function(){ call22(cvalue2);},1000);
}
functioncall22(abcd)
{
var curdate = newDate();
var curtime = curdate.getTime();
var curtime2=parseInt(curtime);
var result=curtime2 - abcd;
if( (result >30000) && (result < 31000) )
{
alert(“POPUPONCETHROUGHOUTTHESITE”);
clearInterval(myVar);
}
}
callagain();
});
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