Can't Manage To Sleep Inside A Loop

I want to pause 1 second for every time it loops, it is usually easy to do similar pauses on other cases, but when working with loops, it seems it get harder: for (var i=0 ; i <

Solution 1:

This function works more like a normal for loop while it isn't

You need to take into account that a for gets 3 arguments inbetween semicolons.

1. Before starting (ie var i=0 you define a variable)
2. A condition before running the code again (ie i < 10 while i is under 10)
3. An action everytime it finishes the code again (i++ add one to i)

Code

(function() {
    // Define a variablevar i = 0,
        action = function() {
            // Condition to run againif (i < 10) {
                document.write(i + "<br>");

                // Add one to i
                i++;
                setTimeout(action, 1000);
            }
        };

    setTimeout(action, 1000);
})();

Here is a jsfiddle for this code demonstrating its working: http://jsfiddle.net/sg3s/n9BNQ/

Solution 2:

You pass the return value of a function call to setTimeout instead of a function. Try the following code:

for (var i = 0; i < 10; i++) {
    (function(i) {
        setTimeout(function() {
            writeMsg(i);
        }, 1000*i);
    })(i);
}

In case you wonder why the call is wrapped inside an anonymous function: Without that function each setTimeout callback would receive the same i so when the callbacks fire it would always be 10. The anonymous function creates a new i inside that is not connected to the loop variable.

Solution 3:

Classic function-in-a-loop problem. One archetypal solution:

functioncreateCallback(i) {
    returnfunction () {
        writeMsg(i);
    };
}

functionwriteMsg (index) {
    document.write (index + "<br>");
}

for (var i=0 ; i < 10 ; i++) {
    setTimeout (createCallback(i), 1000*i);
}

Solution 4:

The 10 timeouts are all based on the time that setTimeout() is called. So, they are all triggered at the same time.

for (var i=0; i < 10; i++) {
    (function(idx){
        setTimeout(function(){
            document.write(idx+"<br/>");
        },1000*idx);
    })(i);
};

Solution 5:

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var var2;
var tmp;
var evt;
var i=0;
var res = document.getElementsByClassName('mar-plp-filter-content nav nav--stacked')[0].children.length;
tmp = document.getElementsByClassName('mar-plp-filter-content nav nav--stacked')[0].children;
functionmyfunc()
{
if(i<res)
{
var2 = tmp[i].getElementsByTagName("span")[0].getElementsByClassName("inverted")[0];
// alert(var2.innerHTML);var evObj = document.createEvent('MouseEvents');
evObj.initEvent( 'mouseover', true, false );
var2.dispatchEvent(evObj);
var2.style.backgroundColor="GREEN";
i++;
setTimeout(myfunc,3000);
}
};
setTimeout(myfunc,3000);